Respuesta :
Answer:
THE MOLECULAR FORMULA FOR THE COMPOUND IS C2 Cl2
Explanation:
mass = 0.04380 g
Volume = 10 mL = 10 / 1000 L = 0.010 L
Pressure = 1.10 atm
R = 0.082 L atm mol^-1 K^-1
Temperature = 290.5 K
Carbon = 25.305 %
Chlorine = 74.695 %
Atomic mass of carbon = 12
Atomic mass of chlorine = 35.5
First calculate the empirical formula by following these steps:
1. Write the percentage composition of the elements involved and divide by its atomic mass
Carbon = 25.305 / 12 = 2.10875
Chlorine = 74.695 /35.5 = 2.1040
2. Divide each by the smaller value
Carbon = 2.10875 / 2.1040 = 1.002
Chlorine = 2.1040 / 2.1040 = 1
3. Round up to the whole number
The empirical formula is C Cl
Next is to calculate the molar mass of the compound using ideal gas equation
PV = mRT/ MM
Mm = mRT / PV
Mm = 0.04380 * 0.082 * 290.5 / 1.10 * 0.010
Mm = 1.0433 / 0.011
Mm = 94.845 g/mol
Mm = 94.85 g/mol
Now that we know the molar mass, we can go on to calculate the molecular formula:
(C Cl) n = Molar mass
( 12 + 35.5) n = 94.85
(47.5)n = 94.85
n = 94.85 / 47.5
n = 1.9968
n ~ 2
The molecular formula can then be written as C2Cl2.
