For the given set, the average is 13.5 years, and the standard deviation is 17.02 years.
What is the average age of the bears?
Here we know that the ages of the bears are {5, 4, 6, 39}, then the average of these 4 values is:
[tex]A = \frac{5 + 4 + 6 + 39}{4} = 13.5[/tex]
So the average age of the bears is 13.5 years.
What is the standard deviation?
The standard deviation for the given set will be:
[tex]S_X = \sqrt{\frac{(5 - 13.5)^2 + (4 - 13.5)^2 + (6 - 13.5)^2 + (39 - 13.5)^2}{4 - 1} } \\\\S_X = 17.02[/tex]
The standard deviation is 17.02 years.
If you want to learn more about sets of data, you can read:
https://brainly.com/question/475676
