Answer:
width is = 26ft
length is = 31ft
Step-by-step explanation:
The area of hall is 806 sq. ft.
length is 5 ft greater than its width.
L = 5+b
L*b = 806
(5+b)*b= 806
5b +b² = 806
B²+5B-806= 0
Solving quadratically
B² +31B -26B -806= 0
B(B+31)-26(B+31)= 0
(B-26)(B+31)= 0
B= 26 or -31
So the value of the width must be positive so the width is = 26ft
If width is 26, length is 26+5 = 31ft
