Answer:
Just pick one step below I guess...
Step-by-step explanation:
I'll just solve it because I don't know which step you're looking for.
Move everything except for the 7 to one side:
[tex]x^2-12x=-7[/tex]
Now take the square of half of the coefficient for the x and add it to both sides.
[tex]x^2-12x+36=29[/tex]
You can see that the side can now be factored.
[tex](x-6)^2=29[/tex]
[tex]x-6=\sqrt{29}[/tex]
[tex]x=\sqrt{29}-6, x=-\sqrt{29} -6[/tex]
The solutions to the quadratic equation are:
[tex]x=6 -\sqrt{29}[/tex] or [tex]x=6 +\sqrt{29}[/tex]
The given equation is:
[tex]x^2=12x-7[/tex]
The equation can be re-written as:
[tex]x^2 - 12x = -7[/tex]
Add [tex]6^2[/tex] to both sides of the equation
[tex]x^2-12x+6^2=-7+6^2\\\\x^2-12x+6^2=-7+36\\\\[/tex]
The expression can be further simplified as:
[tex](x-6)^2=29[/tex]
Take the square root of both sides
[tex]x-6=\pm\sqrt{29} \\\\x=6 \pm\sqrt{29}[/tex]
The solutions to the quadratic equation are:
[tex]x=6 -\sqrt{29}[/tex] or [tex]x=6 +\sqrt{29}[/tex]
Learn more on completing the square here: https://brainly.com/question/10449635
