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A 4 kW vacuum cleaner is powered by an electric motor whose efficiency is 90%. (Note that the electric motor delivers 4 W of net mechanical power to the fan of the cleaner). What is rate at which this vacuum cleaner supplies energy to the room when running

Respuesta :

Answer:[tex]3.6\ kW[/tex]

Explanation:

Given

Power Supplied [tex][tex]P_{input}=4\ kW[/tex][/tex]

Efficiency of the motor [tex]\neta =90\%[/tex]

and [tex]\neta =\dfrac{\text{Power output}}{\text{Power input}}[/tex]

[tex]\Rightarrow 0.9=\dfrac{P_{out}}{4}[/tex]

[tex]\Rightarrow P=0.9\times 4[/tex]

[tex]\Rightarrow P=3.6\ kW[/tex]

So, vacuum cleaner delivers a power of [tex]3.6\ kW[/tex]

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