Answer:
The speed will be "1.06 m/s".
Explanation:
The given values are:
Momentum,
m1 = 244 g
m2 = 45.2 g
On applying momentum conservation ,
Let v2 become the final golf's speed.
From Momentum Conservation
⇒ [tex]Total \ initial \ momentum = Total \ final \ momentum[/tex]
⇒ [tex]m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2[/tex]
On putting the estimated values, we get
⇒ [tex]0.244\times 57.6+0=0.244\times 39.9+45.2\times v2[/tex]
⇒ [tex]57.844+0=9.7356+45.2\times v2[/tex]
⇒ [tex]48.1084=45.2\times v2[/tex]
⇒ [tex]v2=\frac{48.1084}{45.2}[/tex]
⇒ [tex]v2=1.06 \ m/s[/tex]
