Respuesta :
Answer:
Center is [tex](-12,9)[/tex]
Step-by-step explanation:
Given: Equation of a circle is [tex](x+12)^2+(y-9)^2=35[/tex]
To find: center of the circle
Solution:
A circle is a locus of all points which are at equidistant from the fixed point (center).
Equation of a circle is of form [tex](x-a)^2+(y-b)^2=r^2[/tex] where [tex](a,b)[/tex] represents center of the circle and r denotes radius of the circle.
Given equation is [tex](x+12)^2+(y-9)^2=35[/tex]
[tex]\left [ x-(-12) \right ]^2+(y-9)^2=35[/tex]
Compare this equation with [tex](x-a)^2+(y-b)^2=r^2[/tex]
Center is [tex](a,b)=(-12,9)[/tex]
