Answer:
The weight of the pole can be assumed to act at the pole's midpoint, which is 2m from the fence / pivot point, giving us a moment of 490Nm (245N x 2m). We have to counteract this moment by holding the end of the pole. So, we have a lever arm of 3.65m (4.0m - 0.35m), so we would need to exert a force of 134.4N (490N / 3.65m) at a point 35cm from the end of the pole.
Explanation:
happy to help:)
