Answer:
Vertex : (1, -9)
Axis of symmetry : x = 1
x-intercepts : (-2, 0), (4, 0)
y-intercept : (0, -8)
Step-by-step explanation:
Quadratic function to be graphed is,
h(x) = (x - 1)² - 9
By comparing this equation with the vertex form of the parabola,
f(x) = (x - h)² + k
here (h, k) is the vertex of the parabola.
Therefore, vertex of the parabola to be graphed will be (1, -9)
Since coefficient of highest degree term (x²) is positive, parabola will open upwards.
Axis of symmetry of the parabola,
x = 1
For x-intercepts,
(x - 1)² - 9 = 0
(x - 1)² = 9
(x - 1) = ±3
x = 1 ± 3
x = -2, 4
Points of x-intercepts will be (-2, 0), (4, 0).
For y-intercepts, (x = 0)
h(x) = (0 - 1)² - 9
= 1 - 9
= -8
So the point of y-intercept will be (0, -8).
