Answer:
520mL
Explanation:
Data obtained from the question include:
Molarity of stock solution (M1) = 12M
Volume of stock solution (V1) = 130mL
Molarity of diluted solution (M2) = 3M
Volume of diluted (V2) =..?
The volume of the diluted solution can be obtained as follow:
M1V1 = M2V2
12 x 130 = 3 x V2
Divide both side by 3
V2 = 12 x 130 / 3
V2 = 520mL.
Therefore, 520mL of the diluted solution can be prepared.
