jasmine16b
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You pay $8 to play the following game of chance. There is a bag containing 15 balls, 7 are red, 6 are green and the rest are yellow. You will win $14 if you draw a yellow ball, and $11 if you draw a green ball. What is the expected value of the game?

Respuesta :

ethanbaronkim

Answer:

Green ball. $11

Step-by-step explanation:

Let's see.

15 balls. 7 are red. 6 are green. rest are yellow. That means there are 2 yellow balls.

Since there are more greens than yellows, you have a better chance of getting a green. That means you have a higher chance of getting $11

The total expected value of the game is $2 if you pay $8 to play the following game of chance.

What is probability?

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

You pay $8 to play the following game of chance. There is a bag containing 15 balls, 7 are red, 6 are green and the rest are yellow.

Yellow balls = 15 - 7 - 6= 2

Probability of yellow = 2/15

Probability of green = 6/15

Expected value of the game = 6(2/15) + 3(6/15) = $2

Thus, the total expected value of the game is $2 if you pay $8 to play the following game of chance.

Learn more about the probability here:

brainly.com/question/11234923

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