An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?

Respuesta :

Answer:

The velocity is  [tex]v = 5838 \ m/s[/tex]

Explanation:

From the question we are told that

   The electric field is [tex]E = 2.09 kV/m = 2.09 *10^{3} \ V/m[/tex]

    The magnetic field is  [tex]B = 0.358 \ T[/tex]

     

Generally the force experienced by the electron due to the magnetic field is

         [tex]F_m = qvB[/tex]

Generally the force experienced by the electron due to the electric  field is

       [tex]F_e = qE[/tex]

Since from the question the net force is zero  then

     [tex]F_e = F_m[/tex]

=>    [tex]v = \frac{E}{B}[/tex]

Substituting values

      [tex]v = \frac{2.09*10^{3}}{0.358 }[/tex]

    [tex]v = 5838 \ m/s[/tex]

     

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