Answer:
Current, I = 0.073 A
Explanation:
It is given that,
Number of turns in a long solenoid is 1080
Length of the solenoid is 0.420 m
It produces a magnetic field of [tex]10^{-4}\ T[/tex] at its center.
We need to find the current is required in the winding for that to occur. The magnetic field at the center of the solenoid is given by :
[tex]B=\mu_0 NI[/tex]
I is current
[tex]I=\dfrac{B}{\mu_o N}\\\\I=\dfrac{10^{-4}}{4\pi \times 10^{-7}\times 1080}\\\\I=0.073\ A[/tex]
