Respuesta :

Answer:

Step-by-step explanation:

AP = 8, 24 , 40....

a = 8 , d =16 , n =98 , An = ?

an= a +(n-1)d

an = 8+97*16

an=8+1552

an=1560

hope it helps you..

The 98th term of the arithmetic sequence ( 8, 24, 40, . . . ) is 1560 ( One thousand five hundred and sixty ).

What is an arithmetic sequence?

An arithmetic sequence is simply a sequence of numbers in which the difference between the consecutive terms is constant.

The nth term is an arithmetic sequence is expressed as;

aₙ = a₁ + ( n - 1 )d

Where aₙ is the nth term, a₁ is the first term in the sequence and d is the the common difference between terms.

Given the data in the question;

  • n = 98
  • a₁ = 8
  • d = 24 - 8 or 40 - 24 = 16
  • 98th term of the arithmetic sequence a₉₈ = ?

We substitute our given values into the expression above.

aₙ = a₁ + ( n - 1 )d

a₉₈ = 8 + ( 98 - 1 )16

a₉₈ = 8 + ( 97 )16

a₉₈ = 8 + 1552

a₉₈ = 1560

Therefore, the 98th term of the arithmetic sequence ( 8, 24, 40, . . . ) is 1560 ( One thousand five hundred and sixty ).

Learn more about arithmetic sequence here: https://brainly.com/question/15412619

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