When an electron of a hydrogen atom travels from n = 4 to n = 2, a photon of energy 4.165 × 10-19 joules is released. Calculate the wavelength associated with this radiation.

Respuesta :

Answer:

Explanation:

please delete this it was a mistake

yaba15

Answer:

4.77 × 10-7 meters

Explanation:

Energy of photon, E = hν  

Frequency of photon,

Thus, energy of photon,

Therefore, 4.165 × 10-19 joules =

λ =

λ =

λ  = 4.77 × 10-7 meters

The frequency of a photon having energy of 4.165 × 10-34 joules is 4.77 × 10-7 meters.

Q&A Education