the area of square abcd is 7cm^2
show that x^2+4x=3
Answer:
see explanation
Step-by-step explanation:
The area (A) of the square = s² ( s is the measure of the side )
Here s = x + 2 and A = 7 , thus
(x + 2)² = 7 ← expand left side using FOIL
x² + 4x + 4 = 7 ( subtract 4 from both sides )
x² + 4x = 3 ← as required
Answer:
(x + 2)² = 7
x² + 4x + 4 = 7
x² + 4x = 3
Step-by-step explanation: