Enter the equation of the circle with C(-7, 2) and containing the point P(-3,5).

A. r= V[(x-7)2 + (y + 2)2]
B. 5 = v[(x - 3)2 + (y + 5)21
C. 5 = V[(x +7)2 + (y-2)21
D. r= V[(x + 3)2 + (y - 5)21

Enter the equation of the circle with C7 2 and containing the point P35A r Vx72 y 22B 5 vx 32 y 521C 5 Vx 72 y221D r Vx 32 y 521 class=

Respuesta :

Answer:

c) Equation of the circle

  [tex]\sqrt{(x+7)^2+(y-2)^2}=5[/tex]

Step-by-step explanation:

Given center of the circle C(-7,2) and containing the Point P(-3,5)

C P = r

C P  = [tex]\sqrt{(x_{2} -x_{1})^2+(y_{2} -y_{1} })^2 }[/tex]

C P  = [tex]\sqrt{(-3 -(-7))^2+(5 -2})^2 }[/tex]

C P = [tex]\sqrt{16+9} = 5[/tex]

The radius r = 5

The equation of the circle C(-7,2) and radius =5

[tex](x-h)^2+(y-k)^2 = (r)^2[/tex]

[tex](x-(-7))^2+(y-2)^2 = 25[/tex]

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