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Answer:

Austin's hourly wage is $8.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

Tara's hourly wage is x.

Kayte's hourly wage is y.

Austin's hourly wage is z.

Tara earns twice as much per hour as Kayte.

This means that [tex]x = 2y[/tex]

Kayte earns $3 more per hour than Austin.

This means that [tex]y = z + 3[/tex]

As a group, they earn $41 per hour.

This means that [tex]x + y + z = 41[/tex]

What is Austin's hourly wage?​

This is z.

[tex]x + y + z = 41[/tex]

[tex]y = z + 3[/tex] and [tex]x = 2y[/tex], so [tex]x = 2(z + 3) = 2z + 6[/tex]

[tex]x + y + z = 41[/tex]

[tex]2z + 6 + z + 3 + z = 41[/tex]

[tex]4z + 9 = 41[/tex]

[tex]4z = 32[/tex]

[tex]z = \frac{32}{4}[/tex]

[tex]z = 8[/tex]

Austin's hourly wage is $8.

Answer:

Austin's hourly wage is $8.

Step-by-step explanation:

We can write this problem as a system of linear equations.

We define T: Tara's hourly wage, A: Austin's hourly wage and K: Kayte's hourly wage.

Then, if Tara earns twice as much per hour as Kayte, we have:

[tex]T=2K[/tex]

If Kayte earns $3 more per hour than Austin, we have:

[tex]K=A+3[/tex]

And if they earn $41 per hour as a group, we know:

[tex]T+K+A=41[/tex]

We can use all equations to replace in the third one, as:

[tex]T+K+A=41\\\\(2K)+K+A=41\\\\3K+A=41\\\\3(A+3)+A=41\\\\3A+9+A=41\\\\4A=41-9=32\\\\A=32/4=8[/tex]

Austin's hourly wage is $8.

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