Answer:
1.02 × 10³ g
Explanation:
Step 1: Write the balanced equation
2 CaCO₃ + H₂SO₄ ⇒ CO₂ + H₂O + CaSO₄
Step 2: Calculate the moles corresponding to 500 g of sulfuric acid
The molar mass of sulfuric acid is 98.08 g/mol.
[tex]500g \times \frac{1mol}{98.08g} = 5.10mol[/tex]
Step 3: Calculate the moles of calcium carbonate that react with 5.10 moles of sulfuric acid
The molar ratio of CaCO₃ to H₂SO₄ is 2:1. The moles that react of calcium carbonate are (2/1) × 5.10 mol = 10.2 mol
Step 4: Calculate the mass corresponding to 10.2 moles of calcium carbonate
The molar mass of calcium carbonate is 100.09 g/mol.
[tex]10.2mol \times \frac{100.09 g}{mol} =1.02 \times 10^{3} g[/tex]
