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A 10 foot ladder is placed 4-feet from the edge of a building. How far up the building does the ladder reach? Round your answer to the nearest tenth of a foot.
A:10.8 feet
B:9.2 feet
C:2.4 feet
D:3.7 feet

Respuesta :

mysticchacha

Answer:

9.2 feet.  b.)

Step-by-step explanation:

This uses the Pythagorean Theorem

Do you notice that the ladder forms a right triangle with the building.

10 feet  =  hypotenuse length

4 feet  = bottom leg length

x feet = height of building

so   10^2 = 4^2  + x^2

100 = 16 + x^2

84 = x^2

x = root(84)  = 9.16515  feet   about  9.2 feet

MrRoyal

The ladder is 9.2 feet up the building

The length (L) of the ladder is given as:

[tex]L = 10ft[/tex]

The distance (d) from the edge of the building is

[tex]d = 4ft[/tex]

The distance up the ladder is the height (h) of the ladder on the wall.

This is calculated using the following Pythagoras theorem

[tex]L^2 = d^2 + h^2[/tex]

So, we have:

[tex]10^2 = 4^2 + h^2[/tex]

Evaluate the exponents

[tex]100 = 16 + h^2[/tex]

Subtract 16 from both sides

[tex]84 = h^2[/tex]

Take square roots of both sides

[tex]9.2 = h[/tex]

Rewrite as

[tex]h =9.2[/tex]

Hence, the ladder is 9.2 feet up the building

Read more about Pythagoras theorems at:

https://brainly.com/question/20545047

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