Respuesta :
Answer:
Between 395 and 435 out of 457 orders are filled accurately.
Explanation:
457 minus 42 makes 415. To this number we have to add the 95% confidence, which means that there is a 5% high and low difference that we have to take in account on the perfect 415 outcome. 5% of 415 is 20.75 so that leads to a maximum low of 395 (415-20) and a maximum high of 435 (415 + 20).
Answer:
See explaination
Explanation:
We are given that : In 2015, the ethnic category including Del Taco, El Pollo Loco, Fazoli's, Panda Express, Taco Bell, and Taco John's had the fewest inaccuracies, with only 42 of 457 orders classified as inaccurate.
Thus x = number of orders that are filled accurately in the ethnic fast?food category = 457 - 42 = 415
Thus sample proportion of orders are filled accurately in the ethnic fast?food category is :
\hat{p}=\frac{x}{n}
\hat{p}=\frac{415}{457}
\hat{p}=0.9081
Also we have to find 95% confidence interval for the population proportion of orders that are filled accurately in the ethnic fast?food category.
Formula:
( \hat{p} - E \: \: ,\: \: \hat{p} + E )
where
E = Z_{c}\times \sqrt{\frac{\hat{p}\times (1-\hat{p})}{n}}
find Zc value for c =95% confidence level.
Find Area = ( 1 + c) / 2 = ( 1 + 0.95) / 2 = 1.95/2 = 0.9750
Look in z table for area = 0.9750 or its closest area and find corresponding z value.
See attached file for z table
Thus Zc = 1.96
E = Z_{c}\times \sqrt{\frac{\hat{p}\times (1-\hat{p})}{n}}
E = 1.96 \times \sqrt{\frac{0.9081 \times (1-0.9081 )}{457}}
E = 1.96 \times \sqrt{\frac{0.9081 \times 0.0919 }{457}}
E = 1.96 \times \sqrt{0.000183 }
E = 1.96 \times 0.013514
E =0.026487
E =0.0265
Thus we get :
( \hat{p} - E \: \: ,\: \: \hat{p} + E )
( 0.9081 - 0.0265 \: \: ,\: \: 0.9081 + 0.0265 )
( 0.8816 \: \: ,\: \: \: 0.9346 )
Thus a 95% confidence interval for the population proportion of orders that are filled accurately in the ethnic fast?food category is in between ( 0.8816 \: \: ,\: \: \: 0.9346 ) .