Answer:
(a)1/3
(b)2/3
Step-by-step explanation:
This is a 6-sided number cube, therefore total possible outcomes, n(S)=6
(a)Probability of rolling a 2 OR 3 =P(2)+P(3)
[tex]=\dfrac{1}{6} +\dfrac{1}{6} =\dfrac{2}{6}\\= \dfrac{1}{3}[/tex]
(b)Probability of not rolling a 2 OR 3
In probability, the sum of the probability of an event and its complement is always 1.
Therefore:
P(Rolling a 2 or 3)+P(Not rolling a 2 or 3)=1
From part (a) above:
Probability of rolling a 2 OR 3=[tex]\dfrac{1}{3}[/tex]
Therefore:
[tex]\dfrac{1}{3}+$P(Not rolling a 2 or 3)=1\\P(Not rolling a 2 or 3)=1-\dfrac{1}{3}=\dfrac{2}{3}[/tex]
