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One car traveled 120 miles and drove 10 mph hour faster than a second car drove 100 miles. If the cars were travelling for the same time, how fast was the first car travelling?

90 mph
50 mph
60 mph
80 mph

Respuesta :

Answer:

The speed of the first car is 60 mph

Step-by-step explanation:

speed = distance/time

Solve the above equation for distance to get

distance = speed * time

or simply

d = st

Now we use this formula for distance to write an equation for each car.

Let s = speed of second car

Then since the speed of the first car is 10 mph faster, the first car's speed is s + 10.

The time the two cars traveled is equal but unknown, so let the time = t.

First car: speed = s + 10; time = t; distance = 120 miles

d = st

120 = (s + 10)t    

(s + 10)t = 120      Equation 1

Second car: speed = s; time = t; 100 miles

d = st

100 = st

st = 100       Equation 2

Equations 1 and 2 form a system of 2 equations in 2 unknowns.

(s + 10)t = 120

st = 100

Distribute t in the first equation.

st + 10t = 120

From the second equation we know st = 100, so substitute 100 for st.

100 + 10t = 120

10t = 120

t = 2

The time traveled was 2 hours.

Equation 2:

st = 100

Substitute t with 2.

s * 2 = 100

s = 50

The speed of the second car was 50 mph.

The speed of the first car is s + 10.

s + 10 = 50 + 10 = 60

Answer: The speed of the first car is 60 mph

Answer:

C. 60mph

Step-by-step explanation:

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