Answer:
The volume of solution that contains 1.9 moles of NaOH is 3.42 L
Explanation:
To solve the question, we note that the solution contains 1.9 moles of 0.555 M NaOH
Therefore, 1000 mL contains 0.555 moles of NaOH
1000/0.555 mL contains 1 mole of NaOH
1.9 × 1000/0.555 mL contains 1.9 moles of NaOH
Therefore, the volume of solution that contains 1.9 moles of NaOH is 1.9 × 1000/0.555 mL or 3423.42342 mL = 3.42 L.
