A meat baster consists of a squeeze bulb attached to a plastic tube. When the bulb is squeezed and released, with the open end of the tube under the surface of the basting sauce, the sauce rises in the tube to a distance h, as the drawing shows. Using 1.013 × 105 Pa for the atmospheric pressure and 1490 kg/m3 for the density of the sauce, find the absolute pressure PB in the bulb when the distance h is (a) 0.15 m and (b) 0.10 m.

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nuuk nuuk · Answer 1 · 2020-05-06T05:36:40+02:00

Answer:[tex]P_{bulb}=99.11\ kPa[/tex]

Explanation:

Given

When the bulb is squeezed then liquid level rises to height h i.e. pressure decreases inside the bulb which causes rises in the tube

for common elevation i.e. at liquid level pressure must be equal therefore

[tex]P_{bulb}+\rho gh=P_{atm}[/tex]

[tex]P_{bulb}=1.013\times 10^5-1490\times 9.8\times h[/tex]

for [tex]h=0.15\ m[/tex]

[tex]P_{bulb}=1.013\times 10^5-1490\times 9.8\times 0.15[/tex]

[tex]P_{bulb}=101.3\times 10^3-2.1903\times 10^3[/tex]

[tex]P_{bulb}=99.11\ kPa[/tex]

for [tex]h=0.1\ m[/tex]

[tex]P_{bulb}=101.3\times 10^3-1.4602\times 10^3[/tex]

[tex]P_{bulb}=99.83\ kPa[/tex]