Answer:
Work input in = 3,000ft.lb
Explanation:
Question: You wish to lift a weight by a vertical distance(H) of 15 ft. You can
generate a maximum pushing force (E) of 200 lb with an inclined plane that is 30 feet long (L). What is the amount of work you must input in order to move the weight?
Solution:
Effort Force = 200lb
Distance = height = 15ft
Length of inclined plane = 30ft
Recall, Energy you put in = Energy you get out
Hence, work in = work out
Neglecting friction losses
Load force × distance (upward) = effort force × distance (downward)
Work input in = Effort force × distance
Work input in = 200×15
Work input in = 3,000ft.lb
