We have been given that a right circular cone has a height of 12.2 cm and a base with a circumference of 18.5 cm. We are asked to find the volume of the cone to nearest tenth.
We know that circumference of circle is equal to [tex]2\pi r[/tex].
[tex]2\pi r=18.5[/tex]
[tex]r=\frac{18.5}{2\pi}[/tex]
[tex]r=2.944366[/tex]
Now we will use volume of the cone formula to solve our given problem.
[tex]V=\frac{1}{3}\pi r^2 h[/tex]
[tex]V=\frac{1}{3}\pi (2.944366)^2\cdot (12.2)[/tex]
[tex]V=\frac{1}{3}\pi (8.669291141956)\cdot (12.2)[/tex]
[tex]V=\frac{1}{3}\pi (105.7653519318632)[/tex]
[tex]V=\frac{1}{3}(332.2716526334804752)[/tex]
[tex]V=110.7572175[/tex]
Upon rounding to nearest tenth, we will get:
[tex]V\approx 110.8[/tex]
Therefore, the volume of the given cube would be approximately 110.8 cubic centimeter.
