Answer:[tex]c=3.99\approx 4\ kJ/kg-K[/tex]
Explanation:
Given
Current [tex]I=300\ A[/tex]
Voltage [tex]V=270\ V[/tex]
Mass flow rate [tex]m=0.307\ kg/s[/tex]
Inlet temperature is [tex]T_i=15^{\circ}C\approx 288\ K[/tex]
[tex]T_{out}\leq 81^{\circ}C[/tex]
Here heat of Electromagnet is absorbed by liquid
Heat rate of Electromagnet [tex]\dot{Q}=VI[/tex]
[tex]\dot{Q}=270\times 300=81\ kJ/s[/tex]
Heat absorbed by liquid [tex]\dot{Q}=mc(\Delta T)[/tex]
[tex]\dot{Q}=0.307\times c\times (81-15)[/tex]
[tex]81\times 10^3=0.307\times c\times (81-15)[/tex]
[tex]c=3.99\ kJ/kg-K[/tex]
