Answer:
B
Step-by-step explanation:
The equation of a circle in standard form is [tex](x-h)^2+(y-k)^2=r^2[/tex], where (h, k) is the center and r is the radius. The general form is simply the expanded form of the standard. Let's first write the standard form.
Here, the center is (3, -4) and the radius is r = 6, so:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
[tex](x-3)^2+(y+4)^2=6^2[/tex]
Now expand:
x² - 6x + 9 + y² + 8y + 16 = 36
x² + y² - 6x + 8y - 11 = 0
The answer is B.
