Explanation:
The electrical force between charges is given by :
[tex]F_e=\dfrac{kq_eq_p}{r^2}[/tex]
[tex]q_e\ and\ q_p[/tex] are charge on electron and proton respectively.
[tex]F_e=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1^2}\\\\F_e=2.3\times 10^{-28}\ N[/tex]
The Gravitational force between masses is given by :
[tex]F_G=\dfrac{Gm_em_p}{r^2}[/tex]
[tex]m_e\ and\ m_p[/tex] are masses of electron and proton respectively.
[tex]F_G=\dfrac{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}{1^2}\\\\F_G=1.01\times 10^{-67}[/tex]
Ratio of electrical to the gravitational force is :
[tex]\dfrac{F_e}{F_G}=\dfrac{2.3\times 10^{-28}\ N}{1.01\times 10^{-67}\ N}\\\\\dfrac{F_e}{F_G}=2.27\times 10^{39}[/tex]
Hence, this is the required solution.
