Answer:
Explanation:
The problem is based on vibration in string .For it the formula is as follows :
n = k √T , n is frequency of fundamental tone , k is constant for a string of given length and T is tension in the string .
In the first case weight of sphere is equal to tension .
weight = volume of sphere x density of copper x g
= v x 8960 x g
Putting the values
300 = k √ (v x 8960 x g)
300 = k √ 87808v
When the sphere is half submerged
tension is equal to apparent weight of sphere in water
= v x 8960 x g - .5 v x 1000 x 9.8 , v is volume
= 82908v
for second case
n = k √ 82908v
dividing the two equations
n / 300 = [tex]\sqrt{\frac{82908}{87808} }[/tex]
[tex]\frac{n}{300}[/tex] = .9716
n = 291.5 Hz .
Answer:
291.509 Hz
Explanation:
Fundamental frequency, often referred to simply as the fundamental, is defined as the lowest frequency of a periodic waveform.
It is a vital concept in musical instruments and many aspects .
See the attached file for the solution to the given problem.
