Respuesta :
Answer:
C. The claim is not plausible because 10 falls outside of the interval.
The claim that the ambulance service takes an average of 10 minutes to transport a patient to the hospital is false.
Given to us,
- average time to transport a patient = 10 minutes,
- sample of 12 transports yielded at 95% confidence interval is 11.8±1.6 minutes.
Solution
We know that, the confidence interval for any event shows as the interval with lower and upper bounds. Meaning it gives as the mean interval with a maximum and minimum possible values for that interval as well for unknown variables.
[tex]CI = \bar{x} \pm z \dfrac{s}{\sqrt{n}}[/tex]
where,
CI = confidence interval
[tex]\bar{x}[/tex] = sample mean
z = confidence level value
s = sample standard deviation
n = sample size
Similarly, given in sample of 12 transports yielded at 95% confidence interval is 11.8±1.6 minutes.
So, the mean interval is 11.8 minutes, with a lower bound as 10.2 minutes(11.8-1.6) while upper bound as 13.4 minutes(11.8+1.6).
Hence, the claim that the ambulance service takes an average of 10 minutes to transport a patient to the hospital is false.
Learn more about confidence intervals:
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