Answer:
[tex]x^4yz[/tex]
Step-by-step explanation:
[tex]\frac{(x^6y^3z^2)}{(x^2y^2z)}[/tex] (This can be simplified, because when you divide expressions with exponents that have the same bases, you can subtract the exponents from the one with the corresponding base)
[tex]\frac{(x^6y^3z^2)}{(x^2y^2z)}[/tex]
= [tex](x^(^6^-^2^)y^(^3^-^2^)z^(^2^-^1^))[/tex] (Simplify)
= [tex]x^4yz[/tex]
