contestada

A concentric tube heat exchanger for cooling lubricating oil is comprised of a thin-walled inner tube of 25 mm diameter carrying water and an outer tube of 45 mm diameter carrying the oil. The exchanger operates in counterflow with an overall heat transfer coefficient of 60W/m2K and the tabulated average properties given below. If the outlet temperature of the oil is 60oC, plot the temperature as a function of x and determine the total heat transfer, the outlet temperature of the water, and the required length.

Respuesta :

sahir9397

Find the attachment for complete solution

Ver imagen sahir9397
Ver imagen sahir9397
jayilych4real

The correct answers are:

  • Heat transfer = 700 W.
  • LMTD= 40°C.
  • A= 3.170m²
  • L= 40.36m

Calculations and Parameters:

Toil out= 600°C

Toil in= 100°C

Tw in= 30°C

Mw= 0.1 kg/s

Mo= 0.1 kg/s

To calculate the heat loss by oil = heat gained by the water

MoCp= Mw.CpW (Tw out- Tw in)

Q= Mo.Cpo (To in- To out)

0.1 x 1900  (100-60)

Therefore, the heat transfer = 700 W.

0.1 x 1900 (100-60)

= 48.1°C

LMTD= 40°C.

Hence, we also know that,

Q= V.ALMTD

=> 7600= 60 x A x 40

A= 3.170m²

The length of the heat exchanger is=

L= 3.170/IT x (0.025)

L= 40.36m

Read more about heat transfer here:

https://brainly.com/question/16055406

Otras preguntas

Q&A Education