Which equation represents a circle with a center at (-3,-5) and a radius of 6 units?
(x - 3)2 + (1 - 5)2 = 6
(x - 3)2 + (y - 5)2 = 36
(x + 3)2 + (y + 5)2 = 6
(x + 3)2 + (y + 5)2 = 36

Respuesta :

Answer:

(x +3)^2 + (y + 5)^2  = 36

Step-by-step explanation:

Use general circle equation:

(x - h)^2  + (y - k)^2  = r^2

center:  (h, k)

radius : r

(x - (-3))^2 + (y - (-5))^2  = 6^2

(x +3)^2 + (y + 5)^2  = 36

To solve such problems we need to know about the General Equation of the circle.

General Equation of circle

We know, the general equation for a circle is given as,

(x - h)² + (y - k)² = r²,

where

(h, k) is the coordinate of the center(x, y),

r is the radius of the circle.

The correct option is d, which is (x+3)² + (y+5)² = 36.

Explanation

We need, the center of the circle at (-3,-5) and the radius as 6.

therefore,

h = -3,

k = -5,

r = 6.

substituting the value in the general equation for a circle,

(x - h)² + (y - k)² = r²,

[(x-(-3)]² + [(y-(-5)]² = 6²

(x+3)² + (y+5)² = 36,

Therefore, the correct option is d, which is (x+3)² + (y+5)² = 36.

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