Answer:
[tex]2H_3PO_4 + 3Ba(OH)_2[/tex] → [tex]Ba_3(PO_4)_2+6H_2O[/tex]
Explanation:
Phosphoric acid is [tex]H_3PO_4[/tex] and barium hydroxide is [tex]Ba(OH)_2[/tex]. Since this is an acid-base reaction, our products should be water and a salt. Put these given compounds together as the reactants:
[tex]H_3PO_4 + Ba(OH)_2[/tex] → [tex]Ba_3(PO_4)_2+H_2O[/tex]
We need to balance this by making sure there are the same number of each atom on each side of the equation. Right now, on the left, we have:
- 5 H's
- 1 P
- 6 O's
- 1 Ba
On the right, we have:
- 2 H's
- 2 P's
- 5 O's
- 3 Ba's
To balance this, add a coefficient of 2 to the H3PO4, 3 to Ba(OH)2, and 6 to H2O:
[tex]2H_3PO_4 + 3Ba(OH)_2[/tex] → [tex]Ba_3(PO_4)_2+6H_2O[/tex]
