Respuesta :

Answer:8.9cm

Step-by-step explanation:

by Pythagoras rule we have :

Length of diagonal=√(8^2+4^2)

Length=√(8x8+4x4)

Length of diagonal=√(64+16)

Length of diagonal=√(80)

Length of diagonal=8.9

The approximate length of the diagonal of the rectangle to the nearest tenth will be 8.9 cm.

What is a rectangle?

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rectangle, opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at the mid-point.

The length and width of the rectangle are 8 cm and 4 cm.

Then the approximate length of the diagonal of the rectangle to the nearest tenth will be

We know that the Pythagoras theorem

[tex]D = \sqrt{4^2 + 8^2}\\\\D = \sqrt{16+64}\\\\D = \sqrt{80}\\\\D = 8.9\ cm[/tex]

More about the rectangle link is given below.

https://brainly.com/question/10046743

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