Answer:
Step-by-step explanation:
Givens
The best way to find the general form of the circle, it's to use the center-radius form
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
In this case, [tex]h=1[/tex], [tex]k=-3[/tex] and [tex]r=6[/tex]. Replacing all these values in the formula, we have
[tex](x-1)^{2}+(y+3)^{2}=6^{2}[/tex]
Now, we solve each power
[tex]x^{2} -2x+1+y^{2} +6y+9=36\\x^{2} +y^{2} -2x+6y+10-36=0\\x^{2} +y^{2} -2x+6y-26=0[/tex]
Where:
[tex]C=-2\\D=6\\E=-26[/tex]
However, Ben wrote the expression with F as the constant. So,
[tex]E=F=-26[/tex]
Therefore, the value of D is 6 and the value of F is -26.
