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What is the solution to the system of equations below? y = one-half x minus 4 and y = negative 2 x minus 9 (–2, –5) (–2, –3) (2, –3) (2, –13)

Respuesta :

We have been given a system of equations [tex]y=\frac{1}{2}x-4[/tex] and [tex]y=-2x-9[/tex]. We are asked to find the solution of our given system of equations.

To solve our system of equations, we will equate both equations as:

[tex]\frac{1}{2}x-4=-2x-9[/tex]

[tex]\frac{1}{2}x-4+4=-2x-9+4[/tex]

[tex]\frac{1}{2}x=-2x-5[/tex]

[tex]\frac{1}{2}x+2x=-2x+2x-5[/tex]

[tex]\frac{1}{2}x+\frac{4}{2}x=-5[/tex]

[tex]\frac{1+4}{2}x=-5[/tex]

[tex]\frac{5}{2}x=-5[/tex]

[tex]\frac{2}{5}\cdot \frac{5}{2}x=-5\cdot \frac{2}{5}[/tex]

[tex]x=-2[/tex]

Upon substituting [tex]x=-2[/tex] in equation [tex]y=-2x-9[/tex], we will get:

[tex]y=-2(-2)-9[/tex]

[tex]y=4-9[/tex]

[tex]y=-5[/tex]

Therefore, the solution of our given system of equations would be [tex](-2,-5)[/tex] and option A is the correct choice.

Answer:

is A: (–2, –5)

Step-by-step explanation:

i took the test and got it right

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