Respuesta :
Answer:
Amount of heat absorbed by water is 2604.54 J.
Explanation:
Amount of heat absorbed by water = [tex]m_{water}\times C_{water}\times \Delta T_{water}[/tex]
where m represents mass, C represents specific heat and [tex]\Delta T[/tex] represents change in temperature.
Here [tex]m_{water}=75.0[/tex] g , [tex]C_{water}=4.184J/(g.^{0}\textrm{C})[/tex] and [tex]\Delta T[/tex] = (final temperature - initial temperature) = (29.5-21.2) [tex]^{0}\textrm{C}[/tex] = 8.3 [tex]^{0}\textrm{C}[/tex]
So, amount of heat heat absorbed by water
= [tex](75.0g)\times (4.184\frac{J}{g.^{0}\textrm{C}})\times (8.3^{0}\textrm{C})[/tex]
= 2604.54 J
