Answer:
The anode is oxidized and the cathode is reduced, in this way we are facing a redox reaction or oxide reduction.
Where the oxygenated compound oxidizes, and the protonized reduces.
Explanation:
When he says that oxygen is reduced the reaction would be:
OXYGEN + H (+1) -----> OH-
And the reaction where solid aluminum hydroxide is formed will be:
Al (+3) + 3 KOH (aqueous) -------> Al (OH) 3 (solid) + 3 K (+1),
Here we see how aluminum is immersed in an aqueous medium and becomes a solid compound in the form of hydroxide, where when attached to an oxygen, it is oxygenated and oxidized.
This reaction is considered irreversible
