Pete is a politician. He claims that 32% of the households in his district have total household incomes below the poverty level. His opponent, Opal, wants to test this claim. Opal uses p to represent the proportion of households in the district with incomes below the poverty level. She formulates the null hypothesis, H0:p = 0.32, and an alternative, H1:p ≠ 0.32, to reflect her suspicion that Pete is wrong. Opal obtains a simple random sample of 225 households and finds that 87 of them have incomes below the poverty level. Her summary statistics are displayed. Sample size Sample count Sample proportion Standard error One-sample z-statistic n x p SE z 225 87 0.3867 0.0313 1.8077Use software to determine the p-value of the one-sample z-statistic.