Answer:
After 18 hours, the amount of pure technetium that will be remaining is 12.5 grams
Explanation:
To solve the question, we note that the equation for half life is as follows;
[tex]N(t) = N_0 (\frac{1}{2} )^{\frac{t}{t_{1/2}}[/tex]
Where:
N(t) = Quantity of the remaining substance = Required quantity
N₀ = Initial radioactive substance quantity = 100 g
t = Time duration = 18 hours
[tex]{t_{1/2}[/tex] = Half life of the radioactive substance = 6 hours
Therefore, plugging in the values, we have;
[tex]N(t) = 100 (\frac{1}{2} )^{\frac{18}{6}} = 100 (\frac{1}{2} )^{3} = \frac{100 }{8} = 12.5 \ grams[/tex]
Therefore, after 18 hours, the amount of pure technetium that will be remaining = 12.5 grams.
