Answer:
The answer is 91.18 Nm
Explanation:
Solution
Recall that
The length of the rod = 4.99 m
∅ = 26°
Force = 62.5N
Now,
T = r * F
The direction of the torque will be in horizontally northward
The torque magnitude is T =r F sin θ
where ∅ will be the angle between r + F θ= 163°
Therefore,
T = 4.99 * 62.5 * sin 163
T =91.18 Nm
