Respuesta :
Answer:
a). Geometric sequence
b). [tex]S_{t} =\$37185(1+\frac{6}{100})^{(t-1)}[/tex]
c). $46945.21 will be the salary at the start of 5th year.
Step-by-step explanation:
My salary for the first year is $37185.
If I get an increase of 6% every year then the next year salary will be,
[tex]S_{1}=\$37185(1+\frac{6}{100})[/tex]
= $39416.1
Similarly in the second year my salary will be
[tex]S_{2}=\$39416.1(1+\frac{6}{100})[/tex]
= $41781.07
So the sequence becomes $37185, $39416.1 $41781.07.....
And there is a common ratio in each successive term 'r' = 1.06
a). Therefore, it's a geometric sequence.
b). Explicit formula for this sequence will be in the form of
[tex]S_{t} =\$37185(1+\frac{6}{100})^{(t-1)}[/tex]
Where t = duration in years
c). Salary at the start of 5th year,
[tex]S_{(5)}=\$37185(1+\frac{6}{100})^{5-1}[/tex]
[tex]S_{(5)}=\$37185(1.06)^{4}[/tex]
= $46945.21
By using a increasing exponential equation, we will see that:
- a) Geometric sequence.
- b) y = $37,185*(1 + 0.06)^x
- c) $49,761
How to work with exponential equations?
We know that each year your salary increases by a fixed percentage of 6%, then your salary will be modeled with an exponential equation.
A) The sequences that have exponential behavior are the geometric ones, so this would be represented with a geometric sequence.
B) The general formula is:
y = A*(1 + r)^t
Where A is the initial amount and r is the percentage of increase in decimal form, then we can write:
y = $37,185*(1 + 0.06)^x
C) To get this we need to replace x by 5 in the above equation:
y = $37,185*(1 + 0.06)^5 = $49,761
If you want to learn more about exponential functions, you can read:
https://brainly.com/question/11464095