Answer:
[tex]\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}[/tex]
Step-by-step explanation:
Given that
A right triangle has side lengths a, b, and c
Because you did not attached photo of the right triangle so I will assume that:
- Side a is the adjacent (A)
- Side b is the opposite (O)
- Side c is the hypotenuse (H)
(Please have a look at the attached photo)
To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.
[tex]\sin x = \frac{O}{H}\\\cos x = \frac{A}{H}\\\tan x = \frac{O}{A}[/tex]
EX: the sine of x is equal to the side opposite of angle x over the hypotenuse. Hence, we have the expressions of the trigonometric functions as shown below:
[tex]\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}[/tex]
Hope it will find you well
