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Calculate using coulombs: an object has 6 protons and 8 electrons. Calculate the magnitude of the charge of the objects. Thank you.

Respuesta :

Answer:

-3.2 ×1.6 ×10^-19C

Explanation:

Number of proton = 6

Number of electron = 8

To determine the quantity of the charge, we would first find the difference between the number of

protons and electrons. Then multiply the difference by charge 1.6 x 10 -19 C to determine the charge on the object.

Difference between proton and electron is elementary charge

Elementary charge = proton - electron

= 6 - 8

Elementary charge = -2e

Recall, charge (q) = 1.6 ×10^-19C

1e = 1.6 ×10^-19C

Magnitude of the charge of object = -2× (1.6 ×10^-19C)

Magnitude of the charge of object = -3.2 ×1.6 ×10^-19C

The magnitude of the objects will be: [tex]-3.2 *10^{-19}C[/tex]

Given:

Number of proton = 6

Number of electron = 8

Determination for the magnitude:

To determine the quantity of the charge, we would first find the difference between the number of protons and electrons. Then multiply the difference by charge [tex]1.6 * 10^{ -19} C[/tex] to determine the charge on the object.

Difference between proton and electron is elementary charge.

Elementary charge = proton - electron = 6 - 8

Elementary charge = -2e

As we know,

[tex]1e = 1.6 *10^{-19}C[/tex]

Magnitude of the charge of object = [tex]-2* (1.6 *10^{-19}C)=3.2*10^{-19}C[/tex].

Note: Magnitude is irrespective of the sign, thus the answer will be in positive.

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