Answer: I think it's 4.9%
Step-by-step explanation:
I got this from another website so bare with me if this is wrong.
"Find the area of the board (this will be your sample space)
and area covered by the bull's eye (this will be numerator for calculating probability)
area of circle = πr^2
for the board, radius = 18
for the bull's eye, radius = 4
4^2Ï€/18^2Ï€
Pi gets canceled out
Multiply what you have left by 100
4^2/18^2 * 100 = 4.938% or 4.94% which can be rounded to the nearest tenth, which is 4.9%
The probability that a dart is thrown at random within the dartboard will bite the bull’s eye is 4.9%.
Supposing that a considered circle has its radius of 'r' units.
Then, its area is given as:
[tex]Area = \pi r^2 \: \rm unit^2[/tex]
Garrett throws a dart at a circular dartboard. The dartboard has a radius of 18 inches, and the bull’s eye in the center of the dartboard has a radius of 4 inches.
The area of the circle = [tex]\pi r^2 \: \rm unit^2[/tex]
for the board, radius = 18
for the bull's eye, radius = 4
So, the probability that a dart is thrown at random within the dartboard will bite the bull’s eye.
= 4^2Ï€/18^2Ï€
Multiply what you have left by 100
4^2/18^2 x 100
= 4.938% or 4.94%
Learn more about the area ;
https://brainly.com/question/4887838
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