Answer:
The angle between the polarization direction of the eye and the polarization direction of the incident light = 56.1°
Explanation:
For polarization, the relationship between the intensity of transmitted rays (I), intensity of incident rays (Iâ) and the angle between the polarization direction of the eye and the polarization direction of the incident light (θ) is given as
I = Iâ cos²θ
I = intensity of transmitted rays = 263 W/m²
Iâ = intensity of incident rays = 845 W/m²
θ = ?
263 = 845 cos²θ
cos²θ = (263/845) = 0.3112
Cos θ = â0.3112 = 0.5579
θ = cosâťÂš (0.5579)
θ = 56.1°
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