Answer:
2.8 M HNO3
Explanation:
Cu(OH)2 + 2HNO3 ---> Cu(NO3)2 + 2H2O
1 mol 2 mol
The number of moles Cu(OH)2 in the sample:
2.3 mol/L*0.0300L = 0.069 mol
The number of moles HNO3 in the solution of HNO3 that was used for titration
x mol/L*0.0485L = 0.0485x mol
From equation we can see that number of moles HNO3 = 2 times number of moles Cu(OH)2.
So, we can write
0.0485x = 2*0.069
x = 2*0.069/0.0485 = 2.8 M HNO3
